方法一:直接使用字符串切片功能逆转字符串 def strReverse ( strDemo ): return strDemo [:: - 1 ] print ( strReverse ( 'pythontab.com' )) 方法二:遍历构造列表法 循环遍历字符串, 构造列表,从后往前添
方法一:直接使用字符串切片功能逆转字符串
def strReverse(strDemo):return strDemo[::-1]
print(strReverse('pythontab.com'))
方法二:遍历构造列表法
循环遍历字符串, 构造列表,从后往前添加元素, 最后把列表变为字符串
def strReverse(strDemo):
strList=[]
for i in range(len(strDemo)-1, -1, -1):
strList.append(strDemo[i])
return ''.join(strList)
print(strReverse('pythontab.com'))
方法三:使用reverse函数
def strReverse(strDemo):strList = list(strDemo)
strList.reverse()
return ''.join(strList)
print(strReverse('pythontab.com'))
方法四:借助collections模块方法extendleft
import collectionsdef strReverse(strDemo):
deque1=collections.deque(strDemo)
deque2=collections.deque()
for tmpChar in deque1:
deque2.extendleft(tmpChar)
return ''.join(deque2)
print(strReverse('pythontab.com'))
方法五:递归实现
def strReverse(strDemo):if len(strDemo)<=1:
return strDemo
return strDemo[-1]+strReverse(strDemo[:-1])
print(strReverse('pythontab.com'))
方法六:借助基本的Swap操作,以中间为基准交换对称位置的字符
def strReverse(strDemo):strList=list(strDemo)
if len(strList)==0 or len(strList)==1:
return strList
i=0
length=len(strList)
while i < length/2:
strList[i], strList[length-i-1]=strList[length-i-1], strList[i]
i+=1
return ''.join(strList)
print(strReverse('pythontab.com'))
转自https://www.pythontab.com/html/2018/pythonjichu_0426/1283.html