c#解析jobject的数据结构

首先下载newtonsoft.json，增加引用using newtonsoft.json.linq;

把jobject的内容提取出来，jobject的内容格式如下:

{
    "code": 200, 
    "msg": "success", 
    "data": {
        "id": "12345678", 
        "name": "张三", 
        "sex": "男", 
        "result": {
            "access_token": "49d58eacd7811e463429a1ae10b42173", 
            "user_info": [
                {
                    "school": "社会大学", 
                    "major": "软件开发", 
                    "education": "本科", 
                    "score": 97
                }, 
                {
                    "school": "湖南大学", 
                    "major": "软件工程", 
                    "education": "研究生", 
                    "score": 100
                }
            ]
        }
    }
}

代码如下：

1：新建类

public class userinfo
{
    public string id { get; set; }
    public string name { get; set; }
    public string sex { get; set; }
    public string access_token { get; set; }
    public string school { get; set; }
    public string major { get; set; }
    public string education { get; set; }
    public string score { get; set; }
}

2：获取值

jobject result = new jobject();//假设result为数据结构
userinfo userinfo = new userinfo();
userinfo.id = result["data"].value<string>("id");//id
userinfo.name = result["data"].value<string>("name"); //name
userinfo.sex = result["data"].value<string>("sex"); //sex
userinfo.access_token= result["data"]["result"]["access_token"].tostring();//access_token
jarray res = result["data"]["result"].value<jarray>("user_info");
jobject obj = jobject.parse(res[0].tostring());//只获取数据结构中第一个userinfo里的数据信息
userinfo.school = obj.value<string>("school"); //schoool
userinfo.major = obj.value<string>("major");//major
userinfo.education = obj.value<string>("education");//education
userinfo.score= obj.value<string>("score");//score

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