前言：不知道有没有人和我一样，学习python编程的时候有个想法，模似中奖程序，预测中奖号码。废话不多说，直接实操。
一、红球1-32 蓝球1-15
二、中奖规则
一等奖：6个红色球号码+1个蓝色球号码全中。（6+1）red == 6 and blue ==1二等奖：6个红色球号码全中。（6+0）red == 6三等奖：5个红色球号码+1个蓝色球号码。（5+1）red == 5 and blue == 1四等奖：5个红色球号码或者4个红色球号码+1个蓝色球号码red + blue == 5五等奖：4个红色球号码或者3个红色球号码+1个蓝色球号码red + blue == 4 六等奖：2个红色球号码+1个蓝色球号码或者1个红色球号码+1个蓝色球号码或者只有1个蓝(red == 2 and blue == 1) or (red ==1 and blue ==1) or blue == 1
三、random模块使用
nums = []for i in range(6): while True: num = randint(1, 32) if num not in nums: nums.append(num) breakblue = randint(1, 15)nums = sorted(nums)nums.append(blue)
四、1、随机生成6个红球，随机生成1个蓝球。
2、根据规则判断中几等奖
from random import randintdef create_num(): nums = [] for i in range(6): while True: num = randint(1, 32) if num not in nums: nums.append(num) break blue = randint(1, 15) nums = sorted(nums) nums.append(blue) return numsdef pan_duan(nums, buy_num): red = 0 blue = 0 for i in buy_num[:-1]: # 判断中了多少个 if i in nums[:-1]: red += 1 if nums[-1] == buy_num[-1]: # 判断蓝球有没有中 blue +=1 if red == 6 and blue ==1: return 1 elif red == 6: return 2 elif red == 5 and blue == 1: return 3 elif red + blue == 5: return 4 elif red + blue == 4: return 5 elif (red == 2 and blue == 1) or (red ==1 and blue ==1) or blue == 1: return 6 else: return 0nums = create_num()buy_num = [3, 7, 12, 22, 23, 25, 29]print(f"您中了：{pan_duan(nums, buy_num)} 等奖" )sum_count =0for i in range(10000): nums = create_num() # print(nums) count = pan_duan(nums, buy_num) if count != 0: print(f"第{i}次中{count}等奖") sum_count +=1print(f"共中奖：{sum_count}次")
