SG打表题 打表函数如下: #includecstdio#includestdlib.h#includecstring#includequeueusing namespace std;int sg[110],a,b;int find(int i){ if(sg[i]!=-1)return sg[i]; int use[100],j; memset(use,0,sizeof(use)); for(j=a;j=b j=i;j++) use[
          SG打表题
打表函数如下:
#include<cstdio>
#include<stdlib.h>
#include<cstring>
#include<queue>
using namespace std;
int sg[110],a,b;
int find(int i){
    if(sg[i]!=-1)return sg[i];
    int use[100],j;
    memset(use,0,sizeof(use));
    for(j=a;j<=b && j<=i;j++)
        use[find(i-j)]=1;
    j=0;
    while(use[j])j++;
    return sg[i]=j;
}
int main(){
    int n,i;
    scanf("%d %d",&a,&b);
    memset(sg,-1,sizeof(sg));
    for(i=1;i<=a;i++)sg[i]=0;
    sg[0]=1;
    for(i=1;i<=100;i++){
        printf("%d %d\n",i,find(i));
    }
} 
 多试几个a和b就能看出规律了 
#include<cstdio>
#include<stdlib.h>
#include<cstring>
#include<queue>
using namespace std;
int a,b;
int main(){
    int n,i;
    while(scanf("%d %d %d",&n,&a,&b)==3){
        int tem=n%(a+b);
        if(tem==0)tem=a+b;
        if(tem<=a)printf("LOST\n");
        else printf("WIN\n");
    }
} 
 
